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The ratio of magnitude of magnetic induc...

The ratio of magnitude of magnetic induction (B)at any point due to short magnetic dipole and the magnetic potential (V) at that point is given by

A

`(B)/(V)=(sqrt(3cos^(2)theta+1))/(rcostheta)`

B

`(B)/(V)=(r costheta)/(sqrt(3cos^(2)theta+1))`

C

`(B)/(V)=(sqrt(2cos^(2)theta+1))/(rcostheta)`

D

`(B)/(V)=(sqrt(cos^(2)theta+1))/(rcostheta)`

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AI Generated Solution

The correct Answer is:
To find the ratio of the magnitude of magnetic induction (B) at any point due to a short magnetic dipole and the magnetic potential (V) at that point, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Definitions**: - Magnetic induction (B) at a point due to a magnetic dipole is analogous to the electric field due to an electric dipole. - Magnetic potential (V) at a point due to a magnetic dipole is analogous to the electric potential due to an electric dipole. 2. **Use the Formulas for Electric Dipole**: - The electric field (E) at a point due to an electric dipole is given by: \[ E = \frac{P}{4 \pi \epsilon_0 r^3} (3 \cos^2 \theta + 1) \] - The electric potential (V) at a point due to an electric dipole is given by: \[ V = \frac{P \cos \theta}{4 \pi \epsilon_0 r^2} \] 3. **Analogous Relationships**: - For a magnetic dipole, we can replace the electric dipole moment (P) with the magnetic dipole moment (M). - The constant \( \frac{1}{4 \pi \epsilon_0} \) is replaced by \( \frac{\mu_0}{4 \pi} \) for magnetic dipoles. 4. **Write the Formulas for Magnetic Dipole**: - The magnetic induction (B) at a point due to a magnetic dipole: \[ B = \frac{M}{4 \pi r^3} (3 \cos^2 \theta + 1) \] - The magnetic potential (V) at a point due to a magnetic dipole: \[ V = \frac{M \cos \theta}{4 \pi r^2} \] 5. **Calculate the Ratio \( \frac{B}{V} \)**: - Now, we can find the ratio of B to V: \[ \frac{B}{V} = \frac{\frac{M}{4 \pi r^3} (3 \cos^2 \theta + 1)}{\frac{M \cos \theta}{4 \pi r^2}} \] - Simplifying this expression: \[ \frac{B}{V} = \frac{(3 \cos^2 \theta + 1)}{\cos \theta \cdot r} \] - This gives us: \[ \frac{B}{V} = \frac{3 \cos^2 \theta + 1}{r \cos \theta} \] 6. **Final Result**: - The ratio of the magnitude of magnetic induction (B) at any point due to a short magnetic dipole to the magnetic potential (V) at that point is: \[ \frac{B}{V} = \frac{3 \cos^2 \theta + 1}{r \cos \theta} \]
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