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In a hydrogen atom the electrons revolve...

In a hydrogen atom the electrons revolves round the nucleus `6.8xx10^(15)` times per second in a n orbit of radius 0.53 Å.Determine its equivalent magnetic moment`(e=16xx10^(-19)C)`

A

`9.1xx10^(-24)Am^(2)`

B

`9.3xx10^(-24)Am^(2)`

C

`9.0xx10^(-24) Am^(2)`

D

`9.6xx10^(-24)Am^(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
`M=IA=(ev)/(2pir)A=e.f.A.=e.f.pi r^(2)`
`=1.6xx10^(-19)xx6.8xx10^(15)3.14xx(0.53xx10^(-10))^(2)`
`=9.596xx10^(-24)~~9.6xx10^(-24)Am^(2)`
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