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The magnetic potential at a point due to...

The magnetic potential at a point due to pole of strength m at a distance r is

A

`V=(mu_(0))/(4pi) (m)/(r)`

B

`V=(mu_(0))/(pir) (m)/(r^(2))`

C

`V=(mu_(0))/(4pi)(m)/(r^(3))`

D

`V=(mu_(0))/(4pi) (2m)/(r)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the magnetic potential \( V \) at a point due to a magnetic pole of strength \( m \) at a distance \( r \), we can use the analogy between electrostatics and magnetism. The formula for electric potential \( V \) due to a point charge \( Q \) at a distance \( r \) is given by: \[ V = \frac{1}{4 \pi \epsilon_0} \frac{Q}{r} \] Where: - \( \epsilon_0 \) is the permittivity of free space. In magnetism, we can draw an analogy where: - The magnetic pole strength \( m \) corresponds to the electric charge \( Q \). - The constant \( \frac{1}{4 \pi \epsilon_0} \) corresponds to \( \frac{\mu_0}{4 \pi} \), where \( \mu_0 \) is the permeability of free space. Thus, the magnetic potential \( V_m \) at a distance \( r \) from a magnetic pole of strength \( m \) can be expressed as: \[ V_m = \frac{\mu_0}{4 \pi} \frac{m}{r} \] ### Step-by-step Solution: 1. **Identify the analogous quantities**: Recognize that the magnetic pole strength \( m \) corresponds to the electric charge \( Q \), and the constants in the formulas are also analogous. 2. **Write the electric potential formula**: Recall the formula for electric potential due to a point charge: \[ V = \frac{1}{4 \pi \epsilon_0} \frac{Q}{r} \] 3. **Replace quantities with their magnetic counterparts**: Substitute \( Q \) with \( m \) and \( \frac{1}{4 \pi \epsilon_0} \) with \( \frac{\mu_0}{4 \pi} \): \[ V_m = \frac{\mu_0}{4 \pi} \frac{m}{r} \] 4. **Final expression**: The magnetic potential at a distance \( r \) from a magnetic pole of strength \( m \) is: \[ V_m = \frac{\mu_0}{4 \pi} \frac{m}{r} \]
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