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The magnetic potential at a point along ...

The magnetic potential at a point along the axis of a short magnetic dipole is

A

`V=(mu_(0))/(4pi) (M)/(r^(2))`

B

`V=-(mu_(0))/(4pi) (M)/(r^(2)`

C

`V=pm(mu_(0))/(4pi) (M)/(r^(2))`

D

`V=0`

Text Solution

AI Generated Solution

The correct Answer is:
To find the magnetic potential at a point along the axis of a short magnetic dipole, we can follow these steps: ### Step 1: Understand the Magnetic Dipole A magnetic dipole consists of two equal and opposite magnetic poles, denoted as +m (north pole) and -m (south pole), separated by a distance of 2d (where d is half the length of the dipole). ### Step 2: Define the Point of Interest Let’s consider a point P located at a distance r from the center of the dipole along the axis of the dipole. The distance from the north pole to point P is (r - d) and from the south pole to point P is (r + d). ### Step 3: Calculate the Potential Due to Each Pole The magnetic potential \( V \) at a point due to a magnetic pole is given by the formula: \[ V = \frac{\mu_0 m}{4 \pi r} \] For the north pole at distance \( r - d \): \[ V_N = \frac{\mu_0 m}{4 \pi (r - d)} \] For the south pole at distance \( r + d \): \[ V_S = -\frac{\mu_0 m}{4 \pi (r + d)} \] (Note the negative sign for the south pole.) ### Step 4: Find the Net Potential The total magnetic potential \( V \) at point P is the sum of the potentials due to both poles: \[ V = V_N + V_S = \frac{\mu_0 m}{4 \pi (r - d)} - \frac{\mu_0 m}{4 \pi (r + d)} \] ### Step 5: Combine the Potentials To combine the potentials, we need a common denominator: \[ V = \frac{\mu_0 m}{4 \pi} \left( \frac{(r + d) - (r - d)}{(r - d)(r + d)} \right) \] This simplifies to: \[ V = \frac{\mu_0 m}{4 \pi} \left( \frac{2d}{r^2 - d^2} \right) \] ### Step 6: Simplify Under the Short Dipole Approximation For a short magnetic dipole, we assume that \( r \) is much greater than \( d \) (i.e., \( r \gg d \)). Therefore, we can neglect \( d^2 \) in the denominator: \[ V \approx \frac{\mu_0 m}{4 \pi} \left( \frac{2d}{r^2} \right) \] Since \( 2d \) is the magnetic length \( l \) of the dipole, we can express it as: \[ V \approx \frac{\mu_0 m l}{4 \pi r^2} \] ### Step 7: Final Expression Thus, the magnetic potential at a point along the axis of a short magnetic dipole is: \[ V = \frac{\mu_0 m}{4 \pi r^2} \] where \( m \) is the magnetic moment of the dipole.
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