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A current of 2 ampere is passed in a coi...

A current of 2 ampere is passed in a coil of radius 0.5 m and number of turns 20.The magnetic moment of the coil is

A

`0.314 Am^(2)`

B

`0.14A-m^(2)`

C

`314A-m^(2)`

D

`31.4A-m^(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
I=2A,r=0.5m,n=20,M=?
M=nIA
`nlpir^(2)`
`20xx2xx3.14xx0.25`
`=3.14Am^(2)`
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