An electron in an atom revolves around the nucleus in an orbit of radius `0*5 Å`. Calculate the equivalent magnetic moment if the frequency of revolution of electron is `10^(10)MHz`

Options

A. `1.257xx10^(-23)Am^(2)`
B. `2.357xx10^(-23)Am^(2)`
C. `1.157xx10^(-23)Am^(2)`
D. `5.25xx10^(-23)Am^(2)`

Answer

A

Explanation

`r=0.5A^(@),M=?f=10^(10)MHz`
M=IA
`qfpir^(2)`
`=1.6xx10^(-19)xx10^(10)10^(6)xx3.14xx0.25xx10^(-20)`
`=1.257xx10^(-23)Am^(2)`