The magnetic field `B` and the magnetic intensity `H` in a material are found to be `1.6 T and 1000 A m^(-1)` respectively. Calculate the relative permeability `mu`, and the susceptibility `chi` of the material.

Options

A. `1273,1272`
B. `2.3xx10^(3),310^(2)`
C. `1.3 xx 10^(3),5 xx 10^(2)`
D. `4.3 xx 10^(3),3xx 10^(2)`

Answer

A

Explanation

B=1.6 T,H=1000 A/m
`mu_(r) x=?`
`mu_(r)=(mu)/(mu_(0))=(B)/(Hmu_(0)`
` =(1.6)/(1000xx4pixx10^(-7))`ltbrge1273 ltbr`Now mu_(r)=1+x`
`therefore x=mu_(r)-1`
1273-1
1272