The magnetic potential at a point at a distance of 10 cm from mid point of magnetic dipole on a line making an angle of `60^(@)` with axis is `1.5 xx 10^(-7) Wb//m`.The magnetic moment of the dipole is

Options

A. `0.01 Am^(2)`
B. `0.02Am^(2)`
C. `0.03 Am^(2)`
D. `0.04 Am^(2)`

Answer

C

Explanation

`V=(mu_(0))/(4pi)(Mcostheta)/(r^(2)`
`therefore M=(v4pir^(2))/(mu_(0)costheta)=(1.5xx10^(-7)xx10^(-2))/(10^(-7)xxcos60)=0.03Am^(2)`