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Magnetic potential and magnitude of magnetic induction due to short magnetic dipole of moment `2 Am^(2)` axial point at a distance of 20 cm from its centre are

A

`5xx10^(-6) J//Am, 5 xx 10^(-5) T`

B

`5xx10^(6) J//Am, 5 xx 10^(5) T`

C

`5 xx10^(6) J//Am,5 xx10^(5) T`

D

`5xx10^(-6) J//Am,5 xx 10^(-5)T`

Text Solution

Verified by Experts

The correct Answer is:
A

`V=(mu_(0))/(4pi)( M)/(r^(2))`
`4xx10^(-4)=(10^(-7)xx2)/(4xx10^(-2))=5xx10^(-6)J/Am`
`B=(mu_(0))/(4pi)(2M)/(r^(3))=(10^(-7)xx2xx2)/(8xx10^(-3))=0.5xx10^(-4)`
`=5xx10^(-5) T`
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