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A magnet vibrates in amagnetic field of ...

A magnet vibrates in amagnetic field of strength `10^(-4)pi^(2)T.`If the moment of magnet is `0.1Am^(2)` and its moment of inertia is `10^(-5) Kg m^(2)` then the period of oscillation will be

A

0.5

B

2 s

C

0.3185 s

D

3.14 s

Text Solution

Verified by Experts

The correct Answer is:
B
`T=2pisqrt((I)/(MB))=2 pi sqrt(10^(-5)/(0.1xx10^(-4)xxpi^(2)))=2s`
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