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A "bar" magnet of moment M is cut into t...

A "bar" magnet of moment `M` is cut into two identical pieces along the length. One piece is bent in the form of a semi circle. If two pieces are perpendicular to each other, then resultant magnetic moment is

A

`(M//pi)^(2)+(M//2)^(2)`

B

`sqrt((m//pi)^(2)+(M//2)^(2))`

C

`sqrt((m//pi)^(2)-(M//2)^(2))`

D

Zero

Text Solution

Verified by Experts

The correct Answer is:
B

`M'=sqrt(M_(1)^(2)+M_(2)^(2))`
`=sqrt(((2m)/(2pi))^(2)+((M)/(2)))=sqrt(((M)/(pi))^(2)+((M)/(2))^(2))`
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