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A bar magnet of magnetic moment M(1) is ...

A bar magnet of magnetic moment `M_(1)` is axially cut into two equal parts. If these two pieces are arranged perpendiucular to each other, the resultant magnetic moment is `M_(2)`.
Then the vale of `(M_(1))/(M_(2))` is

A

`1:sqrt(2)`

B

`1:1`

C

`sqrt(2):1`

D

`1:2`

Text Solution

Verified by Experts

The correct Answer is:
C

`M_(2)=sqrt(((M_(1))/(2))^(2)+((M_(1))/(2))^(2))=sqrt(2)(M_(1))/(2)`
`therefore M_(1)/M_(2)=(2)/sqrt(2)=sqrt(2)/(1)`
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