A wire of length `L metre ` , carrying a current `I `ampere is bent in the form of a circle . The magnitude of its magnetic moment is …………. ` MKS units ` .

Options

A. `(iL)/(4pi)`
B. `(i^(2)L)/(4pi)`
C. `(iL^(2))/(4pi)`
D. `(iL^(2))/(4)`

Answer

C

Explanation

`M=IA=Ipir^(2)`, Nowl`l=2pir therefore r=(l)/(2pi)`
Thus ,`M=(Ipil^(2))/(4pi^(2))=(Il^(2))/(4pi)`