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At a point on the right bisector of a ma...

At a point on the right bisector of a magnetic dipole the magnetic potential

A

potential varies as `(1)/(r^(2))`

B

Potential is zero at all points on the right bisector

C

field varies as `r^(2)`

D

Field is perpendicular to the axis of dipole

Text Solution

Verified by Experts

The correct Answer is:
A

`V=(mu_(0))/(4pi)(MaStheta)/(r^(2))`
At right side of bisector,`theta=0`
`therefore V oo(1)/(r^(2))`
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