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Magnetic moment of an electron of charge...

Magnetic moment of an electron of charge `e` moving in a circular orbit of radius `r` with speed `v is given by

A

(evr)

B

(evr/4)

C

(evr/2)

D

(evr/8)

Text Solution

Verified by Experts

The correct Answer is:
C

`M=IA`
`=(qV)/(2pir)pi r^(2)=(qVr)/(2)=(evR)/(2)`
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