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A coil carrying current l has radius r...

A coil carrying current l has radius r and number of turns n it is rewound so that radis of new coil is `(r )/(4)` and it carries current l the ratio fo magenic moment of new coil to that of original coil is

A

1

B

`(1)/(2)`

C

`(1)/(4)`

D

`(1)/(8)`

Text Solution

Verified by Experts

The correct Answer is:
C

`M=nIA=nIpir^(2) therefore Moo n r^(2)`
`(M_(2))/(M_(1))=(n_(2))/(n_(1))((r_(2))/(r_(1)))^(2)=(4n_(1))/(n_(1))((r)/(4r))^(2)=(1)/(4)`
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