If a conductor is moving in the north direction and magnetic field is applied vertically upwards, the change in flux is `2xx10^(-4)` Wb within 2s. Is the resistance of conductor is `5Omega`, then the magnitude of induced current will be

Options

A. 0.02 mA
B. 0.2 mA
C. 0.002 mA
D. 2 mA

Answer

A

Explanation

`e=(dphi)/(dt)=(2xx10^(-4))/(2)=1xx10^(-4)V`
`I=(e)/(R)=(1xx10^(-4))/(5)=0.02mA`