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A coil of area 10cm^2 and 10 turns is in...

A coil of area `10cm^2` and 10 turns is in magnetic field directed perpendicular to the plane and changing at a rate of `10^8 gauss//s`. The resistance of coil is `20Omega`. The current in the coil will be

A

`5A`

B

`0.5A`

C

`0.005A`

D

`500A`

Text Solution

Verified by Experts

The correct Answer is:
A
`I=(e)/(R)=(dphi)/(Rdt)=(nAdB)/(Rdt)`
`I=(10xx10xx10^(-4)xx10^(8)xx10^(-4))/(20)=5A`
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