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The self inductance of the coil of 100 t...

The self inductance of the coil of 100 turns, in which a current of 4A produces a flux of 40 Wb is

A

10 H

B

1 H

C

0.1 H

D

0.01 H

Text Solution

Verified by Experts

The correct Answer is:
A

`phi=LI " "thereforeL=(phi)/(I)=(40)/(4)=10H`
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