In a lossless transformer an alternating...

In a lossless transformer an alternating current of `2` amp is flowing in the primary coil. The number of turns in the primary and secondary coils are `100` and `20` respectively. The value of the current in the secondary coil is

0.08 A

0.4 A

`5A`

`10A`

Text Solution

Verified by Experts

The correct Answer is:

`I_(S)=(n_(P))/(n_(S))xxI_(P)=(25xx4)/(20)xx2=10A`

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