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A power transformer is used to step up a...

A power transformer is used to step up an alternating e.m.f. of `220 V` to `11kv` to trannsmit `4.4 kW` of power. If the primary coil has `1000` turns, what is the current rating of the secondary?(Assume `100%` efficiency for the transformer)

A

`4A`

B

`0.4A`

C

`0.04A`

D

`0.2A`

Text Solution

Verified by Experts

The correct Answer is:
B
`P_(P)=I_(P)*e_(P)`
`therefore I_(P)=(P_(P))/(e_(P))=(4.4xx10^(3))/(220)=20A`
`I_(S)=(e_(P))/(e_(S))xxI_(P)=(4.4xx10^(3))/(11xx10^(3))=0.4A`
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