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The peak value of alternating voltage is...

The peak value of alternating voltage is 423 V. its root mean square value is

A

300 V

B

423 V

C

`423sqrt(2)V`

D

zero

Text Solution

Verified by Experts

The correct Answer is:
A
`e_(rms)=(e_(0))/(sqrt(2))=(423)/(1.414)~~300V`
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