Home
Class 12
PHYSICS
A capacitor of capacitive reactance 79.6...

A capacitor of capacitive reactance 79.62 `Omega` and a resistance of 100 `Omega` are connected in series across a.c. source. The phase difference between applied emf and current is

A

`38^(@)32'`

B

`58^(@)`

C

`30^(@)`

D

`45^(@)42'`

Text Solution

Verified by Experts

The correct Answer is:
A
`Z=sqrt(R^(2)+X_(C)^(2))=sqrt(100^(2)+(79.62)^(2))`
`=127.8Omega`
`therefore phi=cos^(-1)((R)/(Z))=cos^(-1)((100)/(127.8))`
`=38^(@)32'`
Promotional Banner

Topper's Solved these Questions

  • ELASTICITY

    NIKITA PUBLICATION|Exercise MCQ|314 Videos

  • ELECTRONS AND PHOTONS

    NIKITA PUBLICATION|Exercise MCQs|162 Videos

Similar Questions

Explore conceptually related problems

In an L-R circuit, an inductance of 0.1 H and a resistance of 1 Omega are connected in series with an ac source of voltage V = 5 sin 10 t. The phase difference between the current and applied voltage will be

In an L-R circuit, an inductance of 0.1 H and a resistance of 1 Omega are connected in series with an ac source of voltage V = 5 sin 10 t. The phase difference between the current and applied voltage will be

An inductance of 0.5 H, a capacitor of capacitance 10^(-9)F and a resistane of 100Omega are connected in series across AC source of emf 10 V. the current through the circuit at resonance is

A inductor of reactance 1 Omega and a resistor of 2 Omega are connected in series to the terminals of a 6 V (rms) a.c. source. The power dissipated in the circuit is

A capacitor of capacitance 2 muF and resistance of 100 Omega are connected in series and an alternating emf of frequency 1 kHz is applied across the combination. The phase difference between applied emf and current is nearly

A 0.01 H inductor and sqrt(3)pi Omega resistance are connected in series with a 220 V, 50 Hz AC source. The phase difference between the current and emf is

In a series A.C. circuit , R=100Omega , X_(L)=300Omega and X_(C )=200Omega . The phase difference between the applied e.m.f. and the current will be

A capacitor of capacitance 100 muF and a coil of resistance 50 Omega and inductance 0.5 H are connected in series with a 110 V, 50 Hz AC source. Find the rms value of the current.

An inductance of 0.5 H, a capacitance of 1muF and a resistance of 100 Omega are connected in series and a source of A.C. emf of r.m.s. value 20 V and frequency 50 Hz is connected across the combination. The average power consumed over one cycle is

NIKITA PUBLICATION-ELECTROMAGNETIC INDUCTION-MCQs
  1. An inductance of 100 mH and a resistance of 100 Omega are connected in...

    Text Solution

    |

  2. A resistance of 50Omega is connected in series with a 10 muF capacitan...

    Text Solution

    |

  3. A capacitor of capacitive reactance 79.62 Omega and a resistance of 10...

    Text Solution

    |

  4. An inductance of 0.5 H, a capacitance of 1muF and a resistance of 100 ...

    Text Solution

    |

  5. The current flowing through a circuit of resistance 109Omega and an in...

    Text Solution

    |

  6. In an LCR circuit, inductive reactance and capacitive reactance was fo...

    Text Solution

    |

  7. In an AC circuit, the current is given by i=5sin(100t-(pi)/2) and the ...

    Text Solution

    |

  8. A 100 W 200 V bulb is connected to a 160 V power supply. The power con...

    Text Solution

    |

  9. In an AC circuit voltage applied is e=220 sin 100 t. if the impedance ...

    Text Solution

    |

  10. An a.c. emf of e=220 sin omega t is applied across the capacitor, the ...

    Text Solution

    |

  11. An a.c. emf of e=220 sin 100pit is passed through the resistance of 1 ...

    Text Solution

    |

  12. In an AC circuit with voltage V and current I, the power dissipated is

    Text Solution

    |

  13. The reactance of capacitor at 50Hz is 10Omega. What will be its reacta...

    Text Solution

    |

  14. Power factor of the AC circuit varies between

    Text Solution

    |

  15. The capacitive reactance of a capacitor is d.c. circuit in ohm is

    Text Solution

    |

  16. The graph between inductive reactance and frequency is

    Text Solution

    |

  17. The alternating emf of e=e(0) sin omegat is applied across LR series c...

    Text Solution

    |

  18. The alternating emf of e=e(0) sin omegat is applied across capacitor C...

    Text Solution

    |

  19. The current leads the voltage by an angle phi which is given by

    Text Solution

    |

  20. The power dissipated in alternating circuit with voltage e=e(0) sin om...

    Text Solution

    |