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The power dissipated in alternating circ...

The power dissipated in alternating circuit with voltage `e=e_(0)` sin `omegat` and current `I=I_(0)sin(omegat-phi)` is

A

`e_(0)I_(0)`

B

`e_(rms)I_(rms)cosphi`

C

`e_(rms)I_(rms)`

D

0

Text Solution

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The correct Answer is:
B
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Knowledge Check

  • The emf and current in a circuit are such that E = E_(0) sin omega t and I - I_(0) sin (omega t - theta) . This AC circuit contains

    A
    `R` and `L`
    B
    `R` and `C`
    C
    only `R`
    D
    only `C`

  • The instantaneous values of emf and the current in a series ac circuit are: E=E_(0) sin omega t and I=I_(0) sin (omegat+pi//3) respectively, then it is:

    A
    Necessarily a RL circuit
    B
    Necessarily a RC circuit
    C
    Necessarily a LCR circuit
    D
    Can be RC or LCR circuit

  • The equation of an alternating voltage is V = 220 sin [omegat + (pi)/(6)] and the equation for current is l = 10 sin (omegat + (pi)/(6)) . The impedance (in ohm) of the circuit is

    A
    11
    B
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