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The phase angle between current and pote...

The phase angle between current and potential difference in an AC circuit contianing of resistance `4Omega` and reactance `3Omega` will be

A

`cos^(-1)(3//5)`

B

`cos^(-1)(3//4)`

C

`sin^(-1)(4//5)`

D

`cos^(-1)(4//5)`

Text Solution

Verified by Experts

The correct Answer is:
D
`cosphi=(R)/(Z)=(R)/(sqrt(R^(2)+X_(L)^(2)))=(4)/(5)`
`thereforephi=cos^(-1)((4)/(5))`
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