An AC circuit consists of a resistor of `5Omega` and inductor of 10 mH connected in series with 50 volt, 50 Hz supply. The capacitance that should be connected in series with the circuit to obtain maximum current is

Options

A. `1014muF`
B. `10.14muF`
C. `1.014muF`
D. `101.4muF`

Answer

A

Explanation

`f=(1)/(2pisqrt(LC))" "therefore f^(2)=(1)/(4pi^(2)LC)`
`therefore C=(1)/(4pi^(2)Lf^(2))`
`=(1)/(4xx9.87xx10xx10^(-3)xx2500)=1014muF`