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An inductance of 0.5 H, a capacitor of c...

An inductance of 0.5 H, a capacitor of capacitance `10^(-9)F` and a resistane of `100Omega` are connected in series across AC source of emf 10 V. the current through the circuit at resonance is

A

`1A`

B

`10A`

C

0.1 A

D

0.01 A

Text Solution

Verified by Experts

The correct Answer is:
C
At resonance, `I=(e)/(R)`
`=(10)/(100)=0.1A`
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