The length l of a wire is shaped to form a coil of 1 turn. This coil has self inductance L. if the same length is bend more sharply to form 3 turns, the self inductance will become/remain

Options

A. L
B. 2L
C. 3L
D. 4L

Answer

C

Explanation

`L=(mu_(0)n^(2)pia)/(2)" "therefore (L_(1))/(L_(2))=((n_(1))/(n_(2)))^(2)(a_(1))/(a_(2))`
`therefore L_(2)=3L`