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Two coils have the mutual inductance of 0.05 H. The current changes in the first coil as `I=I_(0)sin omegat`, where `I_(0)=1A` and `omega=100pi"rad/s"`. The maximum emf induced in secondary coil is

A

`5piV`

B

`7piV`

C

`2.5piV`

D

`piV`

Text Solution

Verified by Experts

The correct Answer is:
A
`e=M(dI)/(dt)=MI_(0)omegacos omegat`
`therefore e_(0)=MI_(0)omega=5piV`
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