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A coil of 40 Omega resistance has 100 tu...

A coil of `40 Omega` resistance has `100` turns and radius `6 mm` us connected to ammeter of resistance of `160 ohms`. Coil is placed perpendicular to the magnetic field. When coil is taken out of the field, `32 mu C` charge flows through it. The intensity of magnetic field will be

A

0.665 T

B

0.656 T

C

0.566 T

D

5.666 T

Text Solution

Verified by Experts

The correct Answer is:
C
`phi=(phi_(1)-phi_(2))/(R)=(nAB)/(R)`
`therefore B=(phiR)/(nA)=0.566T`
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