A coil having an inductance of `1//pi` henry is connected in series with a resistance of `300 Omega`. If 20 volt from a 200 cycle source are impressed across the combination, the value of the phase angle between the voltage and the current is :

Options

A. `tan^(-1)((4)/(3))`
B. `tan^(-1)((3)/(4))`
C. `tan^(-1)((2)/(3))`
D. `tan^(-1)((3)/(2))`

Answer

A

Explanation

`tanphi=(omegaL)/(R)`
`=(2pifL)/(R)=(4)/(3)`
`therefore phi=tan^(-1)((4)/(3))`