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When 100 V DC is applied across a soleno...

When `100 V` DC is applied across a solenoid, a current of `1.0 A` flows in it. When `100 V` AC is applied across the same coil. The current drops to `0.5A`. If the frequency of the ac source is `50 Hz`, the impedance and inductance of the solenoid are

A

`100Omega,5.05Omega`

B

`210Omega,5.50H`

C

`200Omega,5.55H`

D

`200Omega,0.55H`

Text Solution

Verified by Experts

The correct Answer is:
D
`R=(V_(dc))/(I_(dc))`
`=(100)/(1)=100Omega`
`Z=(e_(rns))/(I_(rns))`
`=(100)/(0.5)=200Omega`
`therefore X_(L)=sqrt(Z^(2)-R^(2))=173Omega`
`L=(X_(L))/(2pif)=0.55H`
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