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A coil of 500 turns and mean radius 10 c...

A coil of 500 turns and mean radius 10 cm makes 3000 rotations per minute about one of its diameter in a uniform magnetic field of induction `4xx10^(-2)Wb//m^(2)` perpendicular to its axis of rotation. The rms current through the coil if its resistance is 100 `Omega`, is

A

4.1A

B

1.4A

C

4.4A

D

1.1A

Text Solution

Verified by Experts

The correct Answer is:
B
`e_(0)=nAB2pif`
`I_(rms)=(e_(rms))/(R)`
`=(e_(0))/(Rsqrt(2))=(nAB2pif)/(Rsqrt(2))`
`=(500xx3.14xx10^(-2)xx4xx10^(-2)xx2xx3.14xx50)/(100xx1.414)`
`=1.4A`
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