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When an alternating emf, e=300 sin 100pi...

When an alternating emf, e=300 sin `100pit` volt is applied across a bulb, the peak value of current is found to be 2 A. the average power is

A

100 W

B

200 W

C

300 W

D

400 W

Text Solution

Verified by Experts

The correct Answer is:
C

`overline(P)=(e_(0)I_(0))/(2)`
`=(300xx2)/(2)=300W`
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