An alternating emf of peak value 350 V i...

An alternating emf of peak value 350 V is applied across an a.c. ammeter of resistance `100 Omega`. What is the reading of the ammeter?

A

2.5A

B

1.5A

C

5.2A

D

2.2A

Text Solution

Verified by Experts

The correct Answer is:

A

`I_(rms)=(e_(rms))/(R)`
`=(e_(0))/(sqrt(2)R)=(350)/(1.414xx100)=2.474`
`~~2.5A`

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