A square metal wire loop of side 10 cm and resistance 1 ohm is moved with a constant velocity `(v_0)` in a uniform magnetic field of induction `B=2 weber//m^(2)` as shown in the figure. The magnetic field lines are perpendicular to the plane to the loop (directed into the paper). The loop is connected to a network of resistors each of value 3 ohms. The resistances of hte lead wire OS and PQ are negligible. What should be the speed of the loop so as to have a steady current of 1 milliampere in the loop? Given the direction of current in the loop.

Options

A. 0.04 m/s
B. 0.4 m/s
C. 0.2 m/s
D. 0.02 m/s

Answer

D

Explanation

`I=(e)/(R)=(Blv)/(R)`
`therefore v=(IR)/(Bl)=(1xx10^(-3)xx4)/(2xx0.1)=2xx10^(-2)m//s`