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In a series RC circuit with an AC source...

In a series `RC` circuit with an AC source, `R = 300 Omega, C = 25 muF, epsilon_0= 50 V` and `v = 50/(pi) Hz`. Find the peak current and the average power dissipated in the circuit.

A

0.1 A

B

2 A/s

C

0.02 A

D

1A

Text Solution

Verified by Experts

The correct Answer is:
A

`X_(C)=(1)/(2pifC)=(1)/(2pixx(50)/(pi)xx25xx10^(-6))`
`=(1)/(25xx10^(-4))=4xx10^(2)=400Omega`
`Z=sqrt(R^(2)+X_(C)^(2))=sqrt(9xx10^(4)+16xx10^(4))`
`Z=5xx10^(2)=500Omega`
`I_(0)=(e_(0))/(Z)=(50)/(500)=0.1A`
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