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A coil having effective area A, is held ...

A coil having effective area A, is held with its plane normal to a magnetic field of induction B. The magnetic induction is quickly reduced to `25%` of its initial value in `2s`. Then e.m.f. induced across the coil will be

A

`(3AB)/(8)`

B

`(3AB)/(4)`

C

`(AB)/(4)`

D

`(AB)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
A

`B_(2)=(25)/(100)B_(1)=(B_(1))/(4)`
`e=(phi_(1)-phi_(2))/(dt)=(AB_(1)-AB_(2))/(dt)`
`=(A)/(dt)(B_(1)-B_(2))`
`=(A)/(dt)(B_(1)-(B_(1))/(4))`
`e=(3AB_(1))/(4dt)=(3AB)/(4xx2)=(3AB)/(8)`
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