A conductor of length 10 cm is moved par...

A conductor of length 10 cm is moved parallel to itself with a speed of `10 m//s`, at right to a magentic induction of `10^(-4) Wb//m^(2)`. The e.m.f. Induced in the conductor is

`10^(-4)V`

`10^(-2)V`

`0V`

`10^(-6)V`

Text Solution

Verified by Experts

The correct Answer is:

`e=Blv=10^(-4)xx0.1xx10=10^(-4)V`

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