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An alternating voltage E = 200sqrt(2) si...

An alternating voltage `E = 200sqrt(2) sin (100 t)V` is applied to a `2 mu F` capacitor through an A.C. ammeter. The reading of the ammeter is

A

4 mA

B

40 mA

C

2 mA

D

3 mA

Text Solution

Verified by Experts

The correct Answer is:
B
`I_(0)=(e_(0))/(X_(C))`
`I_(0)=(e_(0))/((1)/(WC))=wce_(0)`
`I=100xx2xx10^(-6)xx200sqrt(2)`
`I_(rms)=(I_(0))/(sqrt(2))=(100xx2xx10^(-6)xx200sqrt(2))/(sqrt(2))=40mA`.
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