In LCR series circuit an ac emf of 2 volt and frequency 50 Hz is applied across the combination. If resistance is `4Omega`, capacitance is `8muF` and inductance is `10^(-2)H` then the voltage across inductor will be

Options

A. (3/5 V)
B. (5/3 V)
C. (2/3 V)
D. (0.0159 V)

Answer

D

Explanation

`I=(e)/(Z)`
`X_(L)=2pifL`
`=2xx3.14xx50xx10^(-2)=3.14Omega`
`X_(C)=(1)/(2pifC)=(1)/(2xx3.14xx50xx8xx10^(-6))`
`=(0.3185xx10^(4))/(8)=(3185)/(8)=397Omega`
`Z=sqrt(R^(2)+(X_(L)-X_(C))^(2))`
`Z=394.6Omega`
`e_(R)=I*X_(L)=(e)/(Z)*X_(L)`
`=(2)/(394.6)xx3.14=0.0159V`.