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Light of wavelength 5000 Å and intensity...

Light of wavelength 5000 Å and intensity of `3.96 xx 10^(-3) watt//cm^(2)` is incident on the surface of photo metal . If 1% of the incident photons only emit photo electrons , then the number of electrons emitted per unit area per second from the surface will be

A

`9.82 xx 10^(17) m^(-2)//2`

B

`9.82 xx 10^(13) m^(-2) // s`

C

`9.82 m^(-2)//s`

D

`none of these

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The correct Answer is:
A
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