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In a transistor, I(c) = 20 mA, I(b) =1 m...

In a transistor, `I_(c)` = 20 mA, `I_(b)` =1 mA. What will be the value of `alpha` ?

A

20/21

B

`1//20`

C

21/20

D

20

Text Solution

Verified by Experts

The correct Answer is:
A
`alpha=(I_(c))/(I_(e))=(I_(c))/(I_(e)+I_(b))=(20)/(20+1)=(20)/(21)`
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