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The transistor working as common base am...

The transistor working as common base amplifier, current gasin is 0.97 and base current is 0.12 mA.

A

5 mA

B

3.88 mA

C

3 mA

D

0.12 mA

Text Solution

Verified by Experts

The correct Answer is:
A
`alpha=(I_(c))/(I_(e))=(I_(c))/(I_(c)+I_(b))`
`therefore I_(c)=alpha(I_(c)+I_(b))`
`therefore I_(c)=(I_(b))/(1-alpha)=(0.12)/(1-0.97)=3.88 mA`
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