A `P-N` junction diode can withstand currents up to `10 mA`. Under forward bias, The diode has a potential drop of `0.5 V` across it which is assumed to be independent of current. The maximum voltage of the battery used to forward bias the diode when a resistance of `200 Omega` is connected in series with it is

Options

A. 3.5 V
B. 2.5 V
C. 6.5 V
D. 4.5 V

Answer

B

Explanation

`I=(V_(c)-V_(b))/(R)`
`V_(e)-V_(b)=I*R`
`V_(c)=IR+V_(b)`
`=10xx10^(-3)xx200+0.5=2.5 V`