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In a half wave rectifier output is taken...

In a half wave rectifier output is taken across a `90 ohm` load resistor. If the resistance of diode in forward biased condition is `10 ohm`, the efficiency of rectification of `ac` power into `dc` power is.

A

0.406

B

0.812

C

0.7308

D

0.3654

Text Solution

Verified by Experts

The correct Answer is:
D
`eta=0.406xx(6)/(R_(l)+r_(f))=(0.406xx90)/(90+10)`
`=36.54%`
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