In a p-n-p transistor circuit, the collector current is 10mA , If 95% of the electrons emitted reach the collector , what is base current ?

Options

A. 0.35 mA
B. 0.25 mA
C. 0.4 mA
D. 0.5 mA

Answer

D

Explanation

`I_(c)=10 mA, I_(b) = ?`
Now `l_(c)` is equal to 95% of `I_(e)`
`therefore I_(c)=(95)/(100) I_(e)`
`I_(e)=(100)/(95) I_(c)=(100)/(95)xx10=(200)/(19)=10.5 ` mA
`I_(b)=I_(e)-I_(c)=10.5-10=0.5` mA