The input resistance of a silicon transistor is `665Omega`. Its base current is changed by `15muA` which results in the change in collector current by `2mA`. This transistor is used as a common emitter amplifier with a load resistance of `5kOmega`. What is the voltage gain of the amplifier.

Options

A. 1002
B. 1004
C. 1006
D. 1008

Answer

A

Explanation

`R_(i)=665 Omega, delta I_(b)=15 muA , deltaI_(c)=2mA`
`R_(0)=5 K Omega, A_(v)= ?`
`A_(v)=beta(R_(0))/(R_(i))=(deltaI_(c))/(deltaI_(b))*(R_(0))/(R_(i))`
`=(2xx10^(-3)xx5xx10^(3))/(15xx10^(-6)xx665)`
`=(10xx10^(6))/(15xx665)`
`=(10000xx10^(3))/(9975)`
`=1.002xx10^(3)`
=1002