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A cell of emf. 4.5 V is connected to a j...

A cell of emf. `4.5 V` is connected to a junction diode whose barrier potential is `0.7 V`. If the external resistance in the circuit is `190 Omega`. The current in the circuit is

A

20 mA

B

2 mA

C

0.2 mA

D

0.02 mA

Text Solution

Verified by Experts

The correct Answer is:
A
`E=4.5 V, V_(b)=0.7 V , R=190 Omega , I=? `
`I=(E-V_(b))/(R)`
`=(45-0.7)/(190)=0.02A=20 mA`
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