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In CE configuration of a transistor, input resistance is 2 `K Omega`, load resistance is `5 k Omega`, current 32 gain is 60. An input signal of 12 mV is applied to the transistor, calculate the voltage gain

A

15

B

150

C

1500

D

1.5

Text Solution

Verified by Experts

The correct Answer is:
B
`R_(i)=2K Omega, R_(0)= 5k Omega , V_(i) = 12 m V, , A_(v)=? Beta=60`
`A_(V)=beta*(R_(0))/(R_(i))`
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